If the area of an equilateral triansle is $81 \sqrt{3} cm^2$, then its semi - perimeter is
A
18 cm
B
36 cm
C
24 cm
D
27 cm
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D
27 cm
(d) 27 cm let a be the length of each side. Then, $\begin{array}{l}\text { Area }=81 \sqrt{3} cm^2 \Rightarrow \frac{\sqrt{3}}{4} \times a^2=81 \sqrt{3} \Rightarrow a^2=81 \times 4 \Rightarrow a=18 cm \\ \text { Semi-perimeter }=\frac{3}{2} a=27 cm\end{array}$
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