If the compressibility of water is $\sigma $ per unit atmospheric pressure, then the decrease in volume $V$ due to $P$ atmospheric pressure will be
A$\sigma P/V$
B$\sigma PV$
C$\sigma /PV$
D$\sigma V/P$
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B$\sigma PV$
b (b) Compressibility = $\frac{{\Delta V/V}}{P}$ ==>$\sigma = \frac{{\Delta V}}{{PV}}$==> $\Delta V = \sigma PV$
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