MCQ
If the concentration of glucose $\left(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\right)$ in blood is $0.72\, \mathrm{~g} \,\mathrm{~L}^{-1}$, the molarity of glucose in blood is $.....\,\times 10^{-3} \mathrm{M}$. (Nearest integer)

(Given: Atomic mass of $\mathrm{C}=12, \mathrm{H}=1, \mathrm{O}=16 \mathrm{u}$ )

  • $4$
  • B
    $7$
  • C
    $9$
  • D
    $11$

Answer

Correct option: A.
$4$
a
molarty $=$ moles/volume

$=\frac{0.72}{180}=4 \times 10^{-3}=\mathrm{M}$

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