MCQ
If the degree of freedom of a gas are $f,$ then the ratio of two specific heats ${C_P}/{C_V}$ is given by
- ✓$\frac{2}{f} + 1$
- B$1 - \frac{2}{f}$
- C$1 + \frac{1}{f}$
- D$1 - \frac{1}{f}$
✓
Answer
Correct option: A.
$\frac{2}{f} + 1$
a
$\frac{{{C_P}}}{{{C_V}}} = \gamma = 1 + \frac{2}{f}$
$\frac{{{C_P}}}{{{C_V}}} = \gamma = 1 + \frac{2}{f}$
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