If the interatomic spacing in a steel wire is $3.0Å$ and ${Y_{steel}}$= $20 \times {10^{10}}N/{m^2}$ then force constant is
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(b)$K = Y{r_0} = 20 \times {10^{10}} \times 3 \times {10^{ - 10}} = 60\;N/m$
$ = 6 \times {10^{ - 9}}N/{Å}$
$ = 6 \times {10^{ - 9}}N/{Å}$
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