Steel and copper wires of same length are stretched by the same weight one after the other. Young's modulus of steel and copper are $2 \times {10^{11}}\,N/{m^2}$ and $1.2 \times {10^{11}}\,N/{m^2}$. The ratio of increase in length
Medium
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(b)$l = \frac{{FL}}{{AY}} \Rightarrow \frac{{{l_S}}}{{{l_{cu}}}} = \frac{{{Y_{cu}}}}{{{Y_S}}}$($F,L$ and $Y$ are constant)
$\frac{{{l_s}}}{{{l_{cu}}}} = \frac{{1.2 \times {{10}^{11}}}}{{2 \times {{10}^{11}}}} = \frac{3}{5}$
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