MCQ
If the maximum velocity and maximum acceleration of a particle executing $SHM$ are equal in magnitude, the time period will be .... $\sec$
- A$1.57$
- B$3.14$
- ✓$6.28$
- D$12.56$
✓
Answer
Correct option: C.
$6.28$
c
$\mathrm{V}_{\max }=\mathrm{a}_{\max }$
$\mathrm{V}_{\max }=\mathrm{a}_{\max }$
$\omega \mathrm{A}=\omega^{2} \mathrm{A} \quad \Rightarrow \quad \omega=1$
$\mathrm{T}=2 \pi=6.28 \mathrm{s}$
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