MCQ
If the points $(1,1) \,(-1,-1)$ $( - \sqrt 3 ,\sqrt 3 )$ are the vertices of a triangle, then this triangle is
- ✓Equilateral
- BRight-angled
- CIsosceles
- DNone of these
Now, $AB = \sqrt {{{( - 1 - 1)}^2} + {{( - 1 - 1)}^2}} = \sqrt {4 + 4} = \sqrt 8 $
$BC = \sqrt {{{( - \sqrt 3 + 1)}^2} + {{(\sqrt 3 + 1)}^2}} = \sqrt 8 $
$CA = \sqrt {{{(1 + \sqrt 3 )}^2} + {{(1 - \sqrt 3 )}^2}} = \sqrt 8 $
i.e., $AB = BC = CA$. So, it is an equilateral triangle.
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