75^ = - Vidyadip

MCQ

$\sin 75^\circ = $

A
$\frac{{2 - \sqrt 3 }}{2}$
✓
$\frac{{\sqrt 3 + 1}}{{2\sqrt 2 }}$
C
$\frac{{\sqrt 3 - 1}}{{ - 2\sqrt 2 }}$
D
$\frac{{\sqrt 3 - 1}}{{2\sqrt 2 }}$

✓

Answer

Correct option: B.

$\frac{{\sqrt 3 + 1}}{{2\sqrt 2 }}$

b
(b) $\sin \,{75^o} = \sin \,\,({90^o} - {15^o}) $

$= \cos \,{15^o} = \cos \,\,({45^o} - {30^o})$

$ = \frac{{\sqrt 3 + 1}}{{2\sqrt 2 }}$.

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