MCQ
If the points $(a{u^2},\;2au)$ and $(a{v^2},\;2av)$ are the extremities of a focal chord of the parabola ${y^2} = 4ax$, then
  • A
    $uv - 1 = 0$
  • $uv + 1 = 0$
  • C
    $u + v = 0$
  • D
    $u - v = 0$

Answer

Correct option: B.
$uv + 1 = 0$
b
(b) Equation of focal chord for the parabola ${y^2} = 4ax,$ passes through the point $(a{u^2},\,2au)$ and $(a{v^2},2av)$

==> $y - 2au = \frac{{2av - 2au}}{{a{v^2} - a{u^2}}}(x - a{u^2})$

==> $y - 2au = \frac{{2a(v - u)}}{{a(v - u)(v + u)}}(x - a{u^2})$

==> $y - 2au = \frac{2}{{(v + u)}}(x - a{u^2})$

If this is focal chord, so it would passes through focus $(a,0)$.

==>$0 - 2au = \frac{2}{{v + u}}(a - a{u^2})$ ==>$ - uv - {u^2} = 1 - {u^2}$, $\therefore $ $uv+1=0.$

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