MCQ
If the radius of a soap bubble is four times that of another, then the ratio of their excess pressures will be
  • $1:4$
  • B
    $4:1$
  • C
    $16:1$
  • D
    $1:16$

Answer

Correct option: A.
$1:4$
a
(a) $\Delta P \propto \frac{1}{r} \Rightarrow \frac{{\Delta {P_1}}}{{\Delta {P_2}}} = \frac{{{r_2}}}{{{r_1}}} = \frac{r}{{4r}} = \frac{1}{4}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The correct value of ${0^o}C$ on the Kelvin scale is ........... $K$
A sphere $P$ of mass $m$ and moving with velocity $v$ undergoes an oblique and  perfectly elastic collision with an identical sphere $Q$ initially at rest. The angle $\theta$ between the velocities of the spheres after the collision shall be .............. $^o$
A ball of mass $160\, g$ is thrown up at an angle of $60^o$ to the horizontal at a speed of $10\, m\,s^{-1}$ . The angular momentum of the ball at the highest point of the trajectcry with respect to the point from which the ball is thrown is nearly ........ $kg\, m^2/s$  $(g\, = 10\, m\,s^{-2})$
A particle is rotating in a circle with uniform speed as shown. The angular momentum of the particle w.r.t. origin is .........
The coefficient of superficial expansion of a solid is $2 \times 10^{-5} {°C^{-1}}$. It's coefficient of linear expansion is
The surface tension of a liquid is $70\,dyne/cm$. In $MKS$ system its value is 
The expansion of unit mass of a perfect gas at constant pressure is shown in the diagram. Here
A particle moves with constant angular velocity in circular path of certain radius and is acted upon by a certain centripetal force $F$. If the angular velocity is doubled, keeping radius the same, the new force will be
particle is projected from level ground. Its kinetic energy $K$ changes due to gravity so $\frac{{{K_{\max }}}}{{{K_{\min }}}} = 9$. The ratio of the range to the maximum height attained during its flight is
A capillary tube is immersed vertically in water and the height of the water column is $x$. When this arrangement is taken into a mine of depth $d$, the height of the water column is $y$. If $R$ is the radius of earth, the ratio $\frac{x}{y}$ is