($\sigma$ stands for Stefan's constant)
or $T = {\left( {\frac{Q}{{\sigma A}}} \right)^{1/4}} = {\left( {\frac{Q}{{\sigma 4\pi {R^2}}}} \right)^{1/4}}$
(Note: Specific heat of the metal $=500 \,J / kg /{ }^{\circ} C$; Heat transfer coefficient from block to air $=50 \,W / m ^2 /{ }^{\circ} C$ )


