If the speed of the wave shown in the figure is $330m/s$ in the given medium, then the equation of the wave propagating in the positive $x-$direction will be (all quantities are in $M.K.S.$ units)
Medium
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(c)Here $A = 0.05m,$ $\frac{{5\lambda }}{2} = 0.025$==> $\lambda = 0.1m$
Now standard equation of wave
$y = A\sin \frac{{2\pi }}{\lambda }(vt - x)$==> $y = 0.05\sin 2\pi (33t - 10x)$
Now standard equation of wave
$y = A\sin \frac{{2\pi }}{\lambda }(vt - x)$==> $y = 0.05\sin 2\pi (33t - 10x)$
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