MCQ
If the string of a conical pendulum makes an angle $\theta$ with horizontal, then square of its time period is proportional to
- ✓$\sin \theta$
- B$\cos \theta$
- C$\tan \theta$
- D$\cot \theta$
✓
Answer
Correct option: A.
$\sin \theta$
a
(a)
(a)
For conical pendulum we know that
$T=2 \pi \sqrt{\frac{l \cos \theta}{g}}$
where $\theta$ is the angle from vertical but in question $\theta$ is given from horizontal hence
$T=2 \pi \sqrt{\frac{l \sin \theta}{g}}$
$T^2 \propto \sin \theta$
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