Question
If $\triangle\text{PQR}\cong\triangle\text{EFD},$ then ED =

Answer

  1. PR
    Solution:
    $\triangle\text{PQR}\cong\triangle\text{EFD},$
    $\Rightarrow\text{ED}=\text{PR}$ (congruent sides of congruent triangles)
    Hence, correct option is (c)

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