If ${u_1}$ and ${u_2}$ are the units selected in two systems of measurement and ${n_1}$ and ${n_2}$ their numerical values, then
A${n_1}{u_1} = {n_2}{u_2}$
B${n_1}{u_1} + {n_2}{u_2} = 0$
C${n_1}{n_2} = {u_1}{u_2}$
D$({n_1} + {u_1}) = ({n_2} + {u_2})$
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A${n_1}{u_1} = {n_2}{u_2}$
a (a) Physical quantity $(p) =$ Numerical value $(n)$ $ \times $ Unit $(u)$
If physical quantity remains constant then $n \propto 1/u$
$\therefore n_1u_1 = n_2u_2$ .
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