MCQ
If $V$ be the accelerating voltage, then the maximum frequency of continuous $X$-rays is given by
- A$\frac{e h}{V}$
- B$\frac{h V}{e}$
- ✓$\frac{e V}{h}$
- D$\frac{h}{e V}$
✓
Answer
Correct option: C.
$\frac{e V}{h}$
$E=e V=h v_{\max } \Rightarrow v_{\max }=\frac{e V}{h}$
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