MCQ
If $\vec{a}+\vec{b}=\hat{i}$ and $\vec{a}=2 \hat{i}-2 \hat{j}+2 \hat{k}$, then $|\vec{b}|$ equals:
  • A
    $\sqrt{14}$
  • B
    3
  • C
    $\sqrt{12}$
  • D
    $\sqrt{17}$

Answer

$\begin{array}{l}\text {Given, } \hat{a}+\hat{b}=\hat{i} \text { and } \vec{a}=2 \hat{i}-2 \hat{j}+2 \hat{k} \\ \Rightarrow \quad 2 \hat{i}-2 \hat{j}+2 \hat{k}+\vec{b}=\hat{i} \Rightarrow \vec{b}=\hat{i}-(2 \hat{i}-2 \hat{j}+2 \hat{k}) \\ \Rightarrow \quad-\hat{i}+2 \hat{j}-2 \hat{k} \\ \therefore \quad|\vec{b}|=\sqrt{(-1)^2+(2)^2+(-2)^2} \\ =\sqrt{1+4+4}=\sqrt{9}=3\end{array}$

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