$\frac{\lambda }{2} = 1m\,.$ Hence $n = \frac{v}{\lambda } = \frac{{360}}{2} = 180\,Hz$.
$(A)$ the intensity of the sound heard at the first resonance was more than that at the second resonance
$(B)$ the prongs of the tuning fork were kept in a horizontal plane above the resonance tube
$(C)$ the amplitude of vibration of the ends of the prongs is typically around $1 \mathrm{~cm}$
$(D)$ the length of the air-column at the first resonance was somewhat shorter than $1 / 4$ th of the wavelength of the sound in air
(Speed of sound $v = 340\, m/s$)