If vm is the velocity of sound in moist air, vd is the velocity of sound in dry air, under identical conditions of pressure and temperature
A$v_m > v_d$
B$v_m < v_d$
C$v_m = v_d$
D$v_m v_d=1$
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A$v_m > v_d$
a (a)The density of moist air (i.e. air mixed with water vapours) is less than the density of dry air
Hence from $v = \sqrt {\frac{{\gamma P}}{\rho }} $ ==> ${v_{moist\,air}} > {v_{dry\,air}}$
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