MCQ
If $x = \sec \theta + \tan \theta ,$ then $x + \frac{1}{x} = $
- A$1$
- ✓$2\sec \theta $
- C$2$
- D$2\tan \theta $
$ \Rightarrow \,x + \frac{1}{x} = \sec \theta + \tan \theta + \frac{1}{{\sec \theta + \tan \theta }}$
$ = \sec \theta + \tan \theta + \sec \theta - \tan \theta = 2\sec \theta $
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