MCQ
If $\text{z}=1-\cos\theta+\text{i}\sin\theta,$ then $|\text{z}|=$
- A$2\sin\frac{\theta}{2}$
- B$2\cos\frac{\theta}{2}$
- C$2\Big|\sin\frac{\theta}{2}\Big|$
- D$2\Big|\cos\frac{\theta}{2}\Big|$
Solution:
$\therefore\text{z}=1-\cos\theta+\text{i}\sin\theta$
$\Rightarrow|\text{z}|=\sqrt{(1-\cos\theta)^2+\sin^2\theta}$
$\Rightarrow|\text{z}|=\sqrt{1+\cos^2\theta-2\cos\theta+\sin^2\theta}$
$\Rightarrow|\text{z}|=\sqrt{1+1-2\cos\theta}$
$\Rightarrow|\text{z}|=\sqrt{2(1-2\cos\theta)}$
$\Rightarrow|\text{z}|=\sqrt{4\sin^2\frac{\theta}{2}}$
$\Rightarrow|\text{z}|=2\Big|\sin\frac{\theta}{2}\Big|$
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