Explauation The hybridisation of If $_{5}$ molecule is $S p^{3} d^{2}$, as the ceutral atom ioduie has 7 valeuce electrons out of which 5 electuons foum 5 sigma bonds with $F$ atoms aud 2 electuons foum 1 lone Lone pair implying the hybrudisation of the ceutral atom is $s p^{3} d^{2}$
The hybruduiation of $I_{3}-$ is $S p^{3} d$. aud it has 3 lone pars aud 2 bond pajrs. If has linear shape
$I_{3}+$ has $\operatorname{sp}^{3}$ hybrudisation and two pairs on central atom, therefore shape would be beut
$A.$ $KF > KI ; LiF > KF$
$B.$ $KF < KI ; LiF > KF$
$C.$ $SnCl _4 > SnCl _2 ; CuCl > NaCl$
$D.$ $LiF > KF ; \quad CuCl < NaCl$
$E.$ $KF < KI ; CuCl > NaCl$
નીચે આપેલા વિકલ્પોમાંથી સાચો જવાબ પસંદ કરો.
$O _{2}^{+}, O _{2}, O _{2}^{-}, O _{2}^{2-}$
ચઢતા બંધક્રમાંકનો સાચો વિકલ્પ શોધો.