MCQ
In a $500\,mL$ capacity vessel $CO$ and $Cl_2$ are mixed to form $COCl_2$. At equilibrium it contains $0.2\,mole$ of $COCl_2$ and $0.1\,mole$ of each of $CO$ and $Cl_2$. The equilibrium constant $K_c$ for reaction, $\;CO + C{l_2}\,\, \rightleftharpoons \,COC{l_2}$ is
  • A
    $5$
  • $10$
  • C
    $15$
  • D
    $20$

Answer

Correct option: B.
$10$
b
Solution : Given,

Volume = 500 ml = 0.5 L                         (1 L = 1000 ml)

The balanced chemical equilibrium reaction is,

                                     

At equilibrium (moles)        0.1        0.1            0.2

First we have to calculate the concentration of each gas molecules.

Formula used :     

Concentration of CO gas = 

Concentration of  gas = 

Concentration of  gas = 

The expression for equilibrium constant for reaction is,

Now put all the given values in this expression, we get the value for equilibrium constant.

Therefore, the equilibrium constant for the given reaction is 10 L/mole.

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