In a common emitter transistor, the current gain is $80.$ What is the change in collector current, when the change in base current is $250 \mu A$
A$80 \times 250 \mu A$
B$(250-80) \mu A$
C$(250+80) \mu A$
D$250 / 80 \mu A$
[CBSE PMT 2000]
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A$80 \times 250 \mu A$
Current gain $\beta=\frac{\Delta i_c}{\Delta i_b} $
$\Rightarrow \Delta i_c=\beta \times \Delta i_b=80 \times 250 \mu \mathrm{A}$.
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