MCQ
In a compound $C, H$ and $N$ atoms are present in $9 : 1 : 3.5$ by weight. Molecular weight of compound is $108$. Molecular formula of compound is
- A${C_2}{H_6}{N_2}$
- B${C_3}{H_4}N$
- ✓${C_6}{H_8}{N_2}$
- D${C_9}{H_{12}}{N_3}$
${C^{12}} \to 12 \times 6 = 72$
${H^1} \to 1 \times 8 = 8$
${N^{14}} \to 14 \times 2 = 28$
Total molecular weight $= 108$
$\therefore $ Molecualr formula $ = {C_6}{H_8}{N_2}$
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$C{l_{2\left( g \right)}} + 3{F_2}_{\left( g \right)} \rightleftharpoons 2C{l_3}_{\left( g \right)};\Delta {H_r} = - 329\,kJ$
Which of the following will increase the quantity of $ClF_3$ in an equilibrium mixture of $Cl_2, F_2$ and $ClF_3$ ?
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Cities
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Shimla
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Bengaluru
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Delhi
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Mumbai
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$p$ in $N/ m^2$
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$1.01 \times 10^5$
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$1.2 \times 10^5$
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$1.02 \times 10^5$
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$1.21 \times 10^5$ |
(A) $\mathrm{Cu}^{+} \rightarrow \mathrm{Cu}^{2+}+\mathrm{Cu}$
(B) $3 \mathrm{MnO}_4^{2-}+4 \mathrm{H}^{+} \rightarrow 2 \mathrm{MnO}_4^{-}+\mathrm{MnO}_2+2 \mathrm{H}_2 \mathrm{O}$
(C) $2 \mathrm{KMnO}_4 \rightarrow \mathrm{K}_2 \mathrm{MnO}_4+\mathrm{MnO}_2+\mathrm{O}_2$
(D) $2 \mathrm{MnO}_4^{-}+3 \mathrm{Mn}^{2+}+2 \mathrm{H}_2 \mathrm{O} \rightarrow 5 \mathrm{MnO}_2+4 \mathrm{H}^{+}$
Choose the correct answer from the options given below:
${N_2}{H_4}(l)\,+\,2{H_2}{O_2}(l)\,\, \to \,{N_2}(g)\,\, + \,4{H_2}O(l);\,\,{\Delta _r}H_1^o\, = \, - 818\,\,kJ/mol$
${N_2}{H_4}(l)\,\, + {O_2}(g)\,\, \to \,{N_2}(g)\,\, + \,2{H_2}O(l);\,\,{\Delta _r}H_2^o\, = \, - 622\,\,kJ/mol$
${H_2}(g)\,\, + 1/2{O_2}(g)\,\, \to \,{H_2}O(l);\,\,{\Delta _r}H_3^o\, = \, - 285\,\,kJ/mol$
......$kJ/mol$