MCQ
In a compound $C, H, N$ atoms are present in $9 : 1 : 3.5$ by weight. Molecular weight of compound is $108$ . Its molecular formula is
- A$C_2H_6N_2$
- B$C_3H_4N$
- ✓$C_6H_8N_2$
- D$C_9H_{12}N_3$
$13.5 \,\mathrm{g} \text { contains } \frac{9}{12} \,\mathrm{mole}$
$108 \,\mathrm{g}$ contains $\frac{9 \times 108}{12 \times 13.5}=6$ mole carbon
i.e., $\mathrm{C}_{6} \mathrm{H}_{8} \mathrm{N}_{2}$
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$\Psi_{2 s}=\frac{1}{2 \sqrt{2 \pi}}\left(\frac{1}{a_0}\right)^{1 / 2}\left(2-\frac{ r }{ a _0}\right) e ^{- r / 2 a _0}$
At $r=r_0$, radial node is formed. Thus, $r_0$ in terms of $a_0$