In a large building, there are $15$ bulbs of $40\ W$, $5$ bulbs of $100\ W, 5$ fans of $80\ W$ and $1$ heater of $1\ kW$. The voltage of electric mains is $220\ V$. The minimum capacity of the main fuse of the building will be ................ $A$
JEE MAIN 2014, Medium
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Total power consumed by electrical appliances in the building, $P_{\text {total }}=2500\, \mathrm{W}$
Watt $=$ Volt $\times$ ampere
$\Rightarrow \quad 2500=\mathrm{V} \times \mathrm{I}$
$\Rightarrow \quad 2500=2201$
$\Rightarrow \quad I=\frac{2500}{220}=11.36 \approx 12\, \mathrm{A}$
(Minimum capacity of main fuse)
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