In the given circuit, the terminal potential difference of the cell is:
JEE MAIN 2024, Diffcult
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$\mathrm{i} =\frac{3}{1+2}=1 \mathrm{~A}$
$\mathrm{v} =\mathrm{E}-\mathrm{ir}$
$=3-1 \times 1=2 \mathrm{~V}$
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