MCQ
In a $PNP$ transistor working as a common-base amplifier, current gain is $0.96$ and emitter current is $7.2\, mA$. The base current is.....$mA$
  • A
    $0.4 $
  • B
    $0.2$
  • $0.29$
  • D
    $0.35$

Answer

Correct option: C.
$0.29$
c
(c)$\alpha = \frac{{{i_c}}}{{{i_e}}}$$=0.96$ and $ie = 7.2\, mA$
$ \Rightarrow {i_c} = 0.96 \times {i_e}$

$= 0.96 × 7.2 = 6.91 \,mA$
$\therefore {i_e} = {i_c} + {i_b}$

$==> 7.2 = 6.91 + ib $

$==> ib = 0.29 \,mA.$

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