In a simple harmonic oscillator, at the mean position - Vidyadip

MCQ

In a simple harmonic oscillator, at the mean position

A
Kinetic energy is minimum, potential energy is maximum
B
Both kinetic and potential energies are maximum
✓
Kinetic energy is maximum, potential energy is minimum
D
Both kinetic and potential energies are minimum

✓

Answer

Correct option: C.

Kinetic energy is maximum, potential energy is minimum

c
(c) $K . E=\frac{1}{2} k\left(A^{2}-x^{2}\right) ; U=\frac{1}{2} k x^{2}$

At the mean position $x=0$

$\therefore K . E .=\frac{1}{2} k A^{2}=$ Maximum and $U=0$

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