MCQ
In a simple harmonic oscillator, at the mean position
  • A
    Kinetic energy is minimum, potential energy is maximum
  • B
    Both kinetic and potential energies are maximum
  • Kinetic energy is maximum, potential energy is minimum
  • D
    Both kinetic and potential energies are minimum

Answer

Correct option: C.
Kinetic energy is maximum, potential energy is minimum
c
(c) $K . E=\frac{1}{2} k\left(A^{2}-x^{2}\right) ; U=\frac{1}{2} k x^{2}$

At the mean position $x=0$

$\therefore K . E .=\frac{1}{2} k A^{2}=$ Maximum and $U=0$

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