Download App

PART - 2 CH : 2 Operations with Integers — MATHS STD 7 — Question

Gujarat BoardEnglish MediumSTD 7MATHSPART - 2 CH : 2 Operations with Integers3 Marks
Question
In a test, (+4) marks are given for every correct answer and (-2) marks are given for every incorrect answer:
Anil scored (-10) marks even though he had 5 correct answers. How many of his answers were incorrect? Did he leave any questions unanswered?
✓

Answer

Anil had 5 correct answers, and each correct answer is worth + 4 marks they 5 × 4 = 20 marks.
From incorrect answers = -10 – 20 = -30.
Each incorrect answer is worth -2 marks
$\therefore \frac{-30}{-2}=15$
Hence, Anil had 15 incorrect answers.
Yes, he leaves some questions unanswered.
Anil answered the question = (Total No. of Questions) – (Anil’s correct answers + Anil’s incorrect answers)
= 25 – (5 + 15)
= 25 – 20
= 5
Hence, Anil left 5 questions unanswered.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "3 Marks Question" from PART - 2 CH : 2 Operations with Integers→PART - 2 CH : 2 Operations with Integers — all question types→MATHS STD 7 question papers→Gujarat Board STD 7 question papers→Gujarat Board question paper generator→

Similar questions

Find the $C.P.$ when: $S.P. = Rs. 924,$ gain $= 10\%$
→
The adjoining figure shows two circles with the same centre. The radius of the larger circle is $10\ cm$ and the radius of the smaller circle is $4\ cm.$ Find:

$i.$ the area of the larger circle
$ii.$ the area of the smaller circle
$iii.$ the shaded area between the two circles.$ (\pi = 3.14)$
→
A public sewer line is being installed along $80\frac{1}{4}\text{m}$ of road. The supervisor says that the labourers will be able to complete $7.5m$ in one day. How long will the project take to complete$?$
→
Express the numbers appearing in the following statements in the standard form:
Diameter of the Sun is $1,400,000,000$ metres.
→
Find the sum:
$\frac{7}{12}+\frac{11}{16}+\frac{9}{24}$
→
Draw a right triangle $ABC$. Use $RHS$ condition to construct another triangle congruent to it.
→
$x + 9 = 13$
→
Draw $\triangle\text{PQR}$ in which $\angle\text{Q}=80^\circ,$ $\angle\text{R}=55^\circ$ and $QR = 4.5\ cm$. Draw the perpendicular bisector of side $QR$.
→
The price of 1 kg of oranges is ₹ 56.50. What is the price of 2.250 kg of oranges? Can we write 56.50 as 56.5 and 2.250 as 2.25 and multiply? Will we get the same product? Why?
→
In the given figure, the arms of two angles are parallel. If $\angle ABC = 70^\circ ,$ then find $\angle DEF$
→