Question
✓
Answer
- 60º
Solution:
we know that
$\angle\text{A}+\angle\text{B}+\angle\text{C}=180^\circ$ .....(Angle sum property)
$\therefore\angle\text{A}=\Big(180\times\frac{3}{6}\Big)=90^\circ$
$\angle\text{B}=\Big(180\times\frac{2}{6}\Big)=60^\circ\ \text{and}$
$\angle\text{C}=\Big(180\times\frac{1}{6}\Big)=30^\circ$
Now,
$\angle\text{ACE}=\angle\text{A}+\angle\text{B}$ .....(Exterior angle is equal to sum of the remote interior angles)
$=90^\circ+60^\circ$
$=150^\circ$
$\angle\text{ACE}=\angle\text{ECD}+\angle\text{ACD}$
$\therefore150^\circ=\angle\text{ECD}+90^\circ$
$\therefore\angle\text{ECD}=60^\circ$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
In the following, write the correct answer.
In $\triangle\text{ABC}$ and $\triangle\text{PQR},$ if AB = AC, $\angle\text{C}=\angle\text{P}$ and $\angle\text{B}=\angle\text{Q}$ then the two triangles are:
→In $\triangle\text{ABC}$ and $\triangle\text{PQR},$ if AB = AC, $\angle\text{C}=\angle\text{P}$ and $\angle\text{B}=\angle\text{Q}$ then the two triangles are:
The value of $(a^2 - b^2)^3 + (b^2 - c^2)^3 + (c^2 - a^2)^3$ is:
→A line segment, when extended indefinitely in one direction is called a:
The figure formed by joining the mid-points of the adjacent sides of a rectangle is a:
- Rhombus.
- Square.
- Rectangle.
- Parallelogram.
The figure formed by joining the mid-points of the adjacent sides of a rhombus is a:
- Rhombus.
- Square.
- Rectangle.
- Parallelogram.
The figure formed by joining the mid-points of the adjacent sides of a rectangle is a:
The equation 2x + 5y = 7 has a unique solution, if x and y are:
There is a number $x$ such that $x^2$ is irrational but $x^4$ is rational. Then, $x$ can be:
→ABCD is a Trapezium in which $\text{AB || DC}$ and $\angle\text{A}=\angle\text{B} = 45^\circ.$ Find $\angle\text{C}$ and $\angle\text{D}$ of the Trapezium.
→