MCQ
In a $\triangle\text{ABC,}$ it is given that base $= 12\ cm$ and height $= 5\ cm.$ Its area is:
- A$60 \mathrm{\sim cm}^2$
- ✓$30 \mathrm{\sim cm}^2$
- C$15 \sqrt{3} \mathrm{\sim cm}^2$
- D$45 \mathrm{\sim cm}^2$
✓
Answer
Correct option: B.
$30 \mathrm{\sim cm}^2$
Area of triangle $=\frac{1}{2}\times$ Base $\times$ Height
Area of $\triangle\text{ABC}=\frac{1}{2}\times12\times5=30\text{ cm}^2$
Area of $\triangle\text{ABC}=\frac{1}{2}\times12\times5=30\text{ cm}^2$
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