Question
In a $\triangle\text{ABC},$ right angled at B, AB = 24cm, BC = 7cm. Determine:
$\sin \text{C}, \cos \text{C}$
$\sin \text{C}, \cos \text{C}$
✓
Answer
$\triangle\text{ABC}$ is right angled at B AB = 24cm, BC = 7cm. Let 'x' be the hypotenuse, By applying Pythagoras $\text{AC}^2=\text{AB}^2+\text{BC}^2$ $\text{x}^2=24^2+7^2$ $\text{x}^2=576+49$ $\text{x}^2=625$ $\text{x}=25$$\sin\text{C}=\frac{\text{Perpendicular}}{\text{Hypotenuse}}=\frac{\text{AB}}{\text{AC}}=\frac{24}{25}$
$\cos\text{C}=\frac{\text{Base}}{\text{Hypotenuse}}=\frac{\text{BC}}{\text{AC}}=\frac{7}{25}$
$\cos\text{C}=\frac{\text{Base}}{\text{Hypotenuse}}=\frac{\text{BC}}{\text{AC}}=\frac{7}{25}$
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