Question
In a Young's double slit experiment, a laser light of $560\,nm$ produces an interference pattern with consecutive bright fringes' separation of $7.2\,mm$. Now another light is used to produce an interference pattern with consecutive bright fringes' separation of $8.1\,mm$. The wavelength of second light is $......nm$

Answer

$\beta \propto \lambda$

$\lambda_{2}=\frac{9}{8} \lambda_{1}$

$\therefore \beta_{2}=\frac{9}{8} \beta_{1}=\frac{9}{8} \times 560=630\,nm$

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