A simple pendulum oscillating in air has period T. The bob of the pendulum is completely immersed in a non-viscous liquid. The density of the

Q: A simple pendulum oscillating in air has period $T.$ The bob of the pendulum is completely immersed in a non-viscous liquid. The density of the liquid is $\frac {1}{16}$ of the material of the bob. If the bob is inside liquid all the time, its period of oscillation in this liquid is

c For a simple pendulum $\mathrm{T}=2 \pi \sqrt{\frac{\mathrm{L}}{\mathrm{g}_{\mathrm{err}}}}$ Situation $1$: when pendulum is in air $\rightarrow g_{\text {eff }}=g$ Situation $2$ :when pendulum is in liquid $\rightarrow g_{e f}=g\left(1-\frac{\rho_{\text {liquid }}}{\rho_{\text {body }}}\right)=g\left(1-\frac{1}{16}\right)=\frac{15 g}{16}$ So, $\frac{\mathrm{T}^{\prime}}{\mathrm{T}}=\frac{2 \pi \sqrt{\frac{\mathrm{L}}{15 \mathrm{g} / 16}}}{2 \pi \sqrt{\frac{\mathrm{L}}{\mathrm{g}}}}$ $\Rightarrow \mathrm{T}^{\prime}=\frac{4 \mathrm{T}}{\sqrt{15}}$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

A simple pendulum oscillating in air has period $T.$ The bob of the pendulum is completely immersed in a non-viscous liquid. The density of the liquid is $\frac {1}{16}$ of the material of the bob. If the bob is inside liquid all the time, its period of oscillation in this liquid is

A$2T\sqrt {\frac {1}{10}}$
B$2T\sqrt {\frac {1}{14}}$
C$4T\sqrt {\frac {1}{15}}$
D$4T\sqrt {\frac {1}{14}}$

JEE MAIN 2019, Diffcult

STD 11 Science
NEET
STD 11 - 13. oscillations
Physics

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