In a Young’s double slit experiment, the slit separation is 0.2 ,… - Vidyadip

MCQ

In a Young’s double slit experiment, the slit separation is $0.2\, cm$, the distance between the screen and slit is $1\,m$. Wavelength of the light used is $5000 Å.$ The distance between two consecutive dark fringes (in $mm$) is

✓
$0.25$
B
$0.26$
C
$0.27$
D
$0.28$

✓

Answer

Correct option: A.

$0.25$

a
(a)Distance between two consecutive dark fringes $\beta = \frac{{\lambda D}}{d}$ $ = \frac{{5000 \times {{10}^{ - 10}} \times 1}}{{0.2 \times {{10}^{ - 2}}}} = 0.25$$mm.$

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