MCQ
In alkaline condition $KMn{O_4}$ reacts as $2KMn{O_4} + 2KOH \to 2{K_2}Mn{O_4} + {H_2}O + O$. The equivalent weight of $KMn{O_4}$ would be (Atomic mass of $K$ $= 39$, $Mn = 55$, $O = 16$)
- ✓$158$
- B$79$
- C$52.7$
- D$31.6$
✓
Answer
Correct option: A.
$158$
(a) ${e^ - } + M{n^{7 + }} \to M{n^{6 + }}$ $\therefore E = \frac{M}{1}$.
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