- A$1$
- B$1.5$
- ✓$2.5$
- D$3.5$
$Cl{O_2} + 2{H_2}O + 5{e^ - } \to C{l^ - } + 4O{H^ - }$
${H_2}{O_2} \to {O_2}$
${H_2}{O_2} + 2O{H^ - } \to {O_2} + 2{H_2}O + 2{e^ - }$
$Cl{O_2} + 2{H_2}O + 5{e^ - } \to C{l^ - } + 4O{H^ - }] \times 2$
${H_2}{O_2} + 2O{H^ - } \to {O_2} + 2{H_2}O + 2e] \times 2$
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$2Cl{O_2} + 5{H_2}{O_2} + 2O{H^ - } \to 2C{l^ - } + 5{O_2} + 5{H_2}O$
$2Cl{O_2} \equiv 5{H_2}{O_2}$
$\therefore $ $Cl{O_2} = 2.5{H_2}{O_2}$
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$(A)$ $m-CH_3OPhCH_2^+$ $(B)$ $p-CH_3OPhCH_2^+$ $(C)$ $PhCH_2^+$ $(D)$ $p-NO_2PhCH_2^+$
$C_2H_4(g) + H_2(g) \to C_2H_6(g)$
.......$kJ$
| Bond | Bond energy $(kJ)$ |
| $C-H$ |
$413$ |
| $C-C$ | $348$ |
| $C=C$ | $610$ |
| $H-H$ | $436$ |
Where $D$ is an isotope of hydrogen