MCQ
In diamond crystal each carbon atom is linked with other carbon atoms. The number of carbon atoms in diamond unit cell is
- A$2$
- B$4$
- ✓$8$
- D$1$
C atoms are also present in one half of the tetrahedral voids. There are 8 tetrahedral voids in fcc structure.
This accounts for remaining $8 \times \frac{1}{2}=4 \mathrm{C}$ atoms
Thus, total $4+4=8 \mathrm{C}$ atoms are present per unit cell of diamond.
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