Solution:
A symbol of the diode is represented like this: In this problem first we have to check the polarity of the diodes. -10 is the lower voltage in the circuit. Now p-side of p-n juction D1 is connected to lower voltage and n-side of D1 to higher voltage. Thus D1 is reverse biased. Now, let us analyse 2nd diode of the given circuit. The p-side of p-n junction D1 is at higher potential and n-side of D2 is at lower potential. Therefore D2 is forward biased.
Hence, current flows through the jucntion from B to A.
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In a compound microscope magnification will be large, if the focal length of the eye piece is
|
(a) Large |
(b) Smaller |
|
(c) Equal to that of objective |
(d) Less than that of objective |
A straight wire carrying a current 
runs along the axis of a circular current 
. Then the force of interaction between the two current carrying conductors is
|
(a) ∞ |
(b) Zero |
(c) |
(d) |
In Young’s double slit experiment, a minimum is obtained when the phase difference of super imposing waves is
|
(a) Zero |
(b) (2n – 1)π |
(c) nπ |
(d) (n + 1) π |
If the distance between parallel plates of a capacitor is halved and dielectric constant is doubled then the capacitance
|
(a) Decreases two times |
(b) Increases two times |
|
(c) Increases four times |
(d) Remain the same |
When photon of energy 4.25 eV strike the surface of a metal A, the ejected photoelectrons have maximum kinetic energy TA eV and de-Brolie wavelength 
. The maximum kinetic energy of photoelectrons liberated from another metal B by photon of energy 4.70 eV is 
If the de-Broglie wavelength of these photoelectrons is 
, then
|
(a) The work function of A is 2.25 eV |
(b) The work function of B is 4.20 eV |
|
(c) |
(d) |
Newton postulated his corpuscular theory on the basis of
|
(a) Newton’s rings |
(b) Colours of thin films |
|
(c) Rectilinear propagation of light |
(d) Dispersion of white light |
What fraction of a radioactive material will get disintegrated in a period of two half-lives
|
(a) Whole |
(b) Half |
(c) One-fourth |
(d) Three-fourth |
