Question
In figure, points G, D, E, F are concyclic points of a circle with centre C

$\angle E C F=70^{\circ}, m(\operatorname{arc} D G F)=200^{\circ}$
Find $m$ (arc DEF) by completing activity.
$ m(\operatorname{arc} E F)=\angle E C F \quad \ldots \ldots[\text { Definition of measure of } \operatorname{arc}]$
$\therefore m(\operatorname{arc} E F)=\square$
$B u t ; m(\operatorname{arc} D E)+m(\operatorname{arc} E F)+m(\operatorname{arc} D G F)=\square \quad \ldots \ldots[\text { Measure of a complete circle] }$
$\therefore m(\operatorname{arc} D E)=\square$
$\therefore m(\operatorname{arc} D E F)=m(\operatorname{arc} D E)+m(\operatorname{arc} E F)$
$\therefore m(\operatorname{arc} D E F)=\text { square } $

Answer

m(arc EF) = ∠ECF ...[Definition of measure of arc]∴ m(arc EF) = 70° ...(i)
But; m(arc DE)+ m(arc EF) + m(arc DGF) = 360° ...[Measure of a complete circle]
∴ m(arc DE) + 70° + 200° = 360°
m(arc DE) = 360° – 270° ...[From (i) and given]
∴ m(arc DE) = 90° ...(ii)
∴ m(arc DEF) = m(arc DE) + m(arc EF)
= 90° + 70° ...[From (i) and (ii)]
∴ m(arc DEF) = 160°

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