Question
✓
Answer
- PR = QS
Solution:
In $\triangle\text{QPR}$ and $\triangle\text{PQS},$
QR = PS (Given)
$\angle\text{RQP} = \angle\text{SPQ}$ (Given)
PQ = PQ (Common)
$\therefore \triangle\text{QPR} ≅ \triangle\text{PQS}$ (SAS Axio)
$\therefore$ PR = QS (C.P.C.T.)
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