In following diagram there is a straight wire carrying a current $I.$ Consider a circular path with radius $(R)$ near it. It $\vec B_T$ is the tangential component of magnetic field then find the value of integral $\int {{{\vec B}_T}.\overrightarrow {dl} } $
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$\mathrm{B}_{\mathrm{out}}=\frac{\mu_{0} \mathrm{I}}{2 \pi(2 \mathrm{a})}.........(1)$
$B_{\text {in }}=\frac{\mu_{0} I(a / 2)}{2 \pi(a)^{2}}.........(2)$
From $( 1)$$\&(2)$
$\frac{B_{\text {out }}}{B_{\text {in }}}=\frac{\mu_{0} I / 4 \pi a}{\mu_{0} I / 4 \pi a}=\frac{1}{1}$
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