In given diagram ideal voltmeter V reads 1.45,V then relation between r_1 and r

Q: In given diagram ideal voltmeter $V$ reads $1.45\,V$ then relation between $r_1$ and $r_2$ is

b By parallel combination $I=\frac{1.5-1.3}{r_{1}+r_{2}}=\frac{0.2}{r_{1}+r_{2}}$ $\mathrm{V}=1.3+\mathrm{Ir}_{1}$ $1.45=1.3+\frac{0.2 \mathrm{r}_{1}}{\mathrm{r}_{1}+\mathrm{r}_{2}}$ $\Rightarrow 0.15=\frac{0.2 \mathrm{r}_{1}}{\mathrm{r}_{1}+\mathrm{r}_{2}}$ $\Rightarrow 3\left(\mathrm{r}_{1}+\mathrm{r}_{2}\right)=4 \mathrm{r}_{1}$ $\Rightarrow 3 r_{2}=r_{1}$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

In given diagram ideal voltmeter $V$ reads $1.45\,V$ then relation between $r_1$ and $r_2$ is

A$r_1 = 2r_2$
B$r_1 = 3r_2$
C$r_2 = 2r_1$
D$r_2 = 3r_1$

Diffcult

STD 11 Science
NEET
STD 12 - 3. current electricity
Physics

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