Two electric bulbs whose resistances are in the ratio of $1 : 2$ are connected in series. The powers dissipated in them have the ratio
AIPMT 1997, Easy
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(a) In series, current is same in both the bulbs, hence $P \propto R\,(P = {i^2}R)$
$\therefore \frac{{{P_1}}}{{{P_2}}} = \frac{{{R_1}}}{{{R_2}}} = \frac{1}{2}$
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