In given figure, $X$ and $Y$ are two long straight parallel conductors each carrying a current of $2\,\, A.$ The force on each conductor is $F$ newtons. When the current in each is changed to $1\, A $ and reversed in direction, the force on each is now
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$F=\frac{\mu_{0}}{4 \pi} \frac{2 I_{1} I_{2}}{d}$
$F=\frac{\mu_{0}}{4 \pi} \frac{2 \times 2 \times 2}{d} \times l$
$F^{\prime}=\frac{\mu_{0}}{4 \pi} \frac{2 \times 1 \times 1}{d} \times l=\frac{F}{4}$
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