MCQ
In Lassaigne's test, a blue colour is obtained if the organic compound contains nitrogen. The blue colour is due to the formation of :
  • A
    $ \mathrm{K}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right] $
  • $\mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3 $
  • C
    $ \mathrm{Na}_3\left[\mathrm{Fe}(\mathrm{CN})_6\right] $
  • D
    $\mathrm{Cu}_2\left[\mathrm{Fe}(\mathrm{CN})_6\right] $

Answer

Correct option: B.
$\mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3 $
If nitrogen is present in the organic compound then sodium extract contains $\text{NaCN}.$
$\text{Na}+\text{C}+\text{N}\xrightarrow{\text{Fuse}}\text{NaCN}$
$\text{FeSO}_4+6\text{NaCN}\rightarrow\text{Na}_4[\text{Fe(CN)}_6]+\text{Na}_2\text{SO}_4$
It changes to prussian blue $\mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3$ on reaction with $\mathrm{FeCl}_3$.
$4\text{FeCl}_3+3\text{Na}_4[\text{Fe(CN)}_6]\rightarrow\text{Fe}_4[\text{Fe(CN)}_6]_3+12\text{NaCl}$

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